Given $|\vec{A}_1| = 2$,$|\vec{A}_2| = 3$,and $|\vec{A}_1 + \vec{A}_2| = 3$. Find the value of $|(\vec{A}_1 + 2\vec{A}_2) \times (3\vec{A}_1 - 4\vec{A}_2)|$.

The angle between force $\vec{F}=3 \hat{i}+4 \hat{j}-5 \hat{k}$ and displacement $\vec{d}=5 \hat{i}+4 \hat{j}+3 \hat{k}$ is

If $\overrightarrow {A} = 2\hat i + 3\hat j - \hat k$ and $\overrightarrow {B} = - \hat i + 3\hat j + 4\hat k$,a unit vector perpendicular to both $\overrightarrow {A}$ and $\overrightarrow {B}$ will be

If the vector $(\hat{a} + 2\hat{b})$ is perpendicular to the vector $(5\hat{a} - 4\hat{b})$,then the angle between $\hat{a}$ and $\hat{b}$ is ........ $^\circ$.

The angle between two vectors given by $6\hat i + 6\hat j - 3\hat k$ and $7\hat i + 4\hat j + 4\hat k$ is

The angle between $(\overrightarrow{A} - \overrightarrow{B})$ and $(\overrightarrow{A} \times \overrightarrow{B})$ is $(\overrightarrow{A} \neq \overrightarrow{B})$. (in $^{\circ}$)